10(y^2+4y-6)=180

Solution for 10(y^2+4y-6)=180 equation:

10(y^2+4y-6)=180

We move all terms to the left:

10(y^2+4y-6)-(180)=0

We multiply parentheses

10y^2+40y-60-180=0

We add all the numbers together, and all the variables

10y^2+40y-240=0

a = 10; b = 40; c = -240;
Δ = b2-4ac
Δ = 402-4·10·(-240)
Δ = 11200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11200}=\sqrt{1600*7}=\sqrt{1600}*\sqrt{7}=40\sqrt{7}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-40\sqrt{7}}{2*10}=\frac{-40-40\sqrt{7}}{20}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+40\sqrt{7}}{2*10}=\frac{-40+40\sqrt{7}}{20}
$